Division durch Null

In this case you can use the [b]Try…Catch…End[/b] statement.

Example:
[code]
Dim a, b
a = 1.
b = 0
Try
return a/b
Catch Exception
return ?
End
[/code]

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There is a difference if the Y component of the signal contains integer or floating point values. If the signal contains integer values an exception will be thrown in case of a division by zero (see sample above).
With floating point values no exception is thrown, but the result will contain an invalid value (?) at the places where a division by zero occured.
The different behavior stems from the fact that there is no possibility to express an invalid value with integer values.

This what you have to do: Execute the division as usual. Search and replace the invalid values by 0 afterwards:
[code]
dim a, b, c

a = { 1., 2., 3., 4., 5., 6. }
b = { 3, 0, 2, 0, 11, 0 }
c = a / b
c[SearchVoidValues(c)] = 0
[/code]
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