create N times a 3×3 matrix in a formula

Ce sujet contient 2 réponses, 2 participants et a été mis à jour pour la dernière fois par Norbert Bakkers, le il y a 14 années et 4 mois.

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13.01.2011 à 23:50 #33692

Norbert Bakkers
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When anaysing data I need to create a 3×3 matrix for every timestep (N) (every timestep has it’s own unique 3×3 matrix)

The matrix should have the following form
Matrix = [1 to 3, 1 to 3, 1 to N]

So for N=1 I have
[A11_1 A12_1 A13_1
A21_1 A22_1 A23_1
A31_1 A32_1 A33_1]

For N=2 the matrix contains:
[A11_2 A12_2 A13_2
A21_2 A22_2 A23_2
A31_2 A32_2 A33_2]

This function would be similar to the matlab function [i]Matrix(1:3,1:3,1:N)=0[/i]

13.01.2011 à 23:50 #33694

Norbert Bakkers
Participant

When anaysing data I need to create a 3×3 matrix for every timestep (N) (every timestep has it’s own unique 3×3 matrix)

The matrix should have the following form
Matrix = [1 to 3, 1 to 3, 1 to N]

So for N=1 I have
[A11_1 A12_1 A13_1
A21_1 A22_1 A23_1
A31_1 A32_1 A33_1]

For N=2 the matrix contains:
[A11_2 A12_2 A13_2
A21_2 A22_2 A23_2
A31_2 A32_2 A33_2]

This function would be similar to the matlab function [i]Matrix(1:3,1:3,1:N)=0[/i]

14.01.2011 à 18:28 #33693

Bernhard Kantz
Participant

You could solve this problem with two formulas. The first formula is a user-defined FPScript function and the second formula returns a list. Please see more details in the FlexPro help.

Formula Matrix:
[code]
Arguments n
{(3,1,1), (3,1,1), (3,1,(n-1)/2.)}
[/code]

Formula ListResult
[code]
Dim timestamp = {3,6,9}
Dim result
For Each Row i In timestamp Do
result := [timestamp[i], Matrix(Timestamp[i])]
End
result
[/code]

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