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VBA File Browser

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  • Autor
    Puestos
  • #35224
    HerveM1234
    Participante

    Hi,

    Why the syntax : [code]
    fileToOpen = Application _
    .GetOpenFilename(“Text Files (*.txt), *.txt”)
    If fileToOpen <> False Then
    MsgBox “Open ” & fileToOpen
    End If
    [/code]
    returns “error 438” ?

    How to browse directories using FlexPro VBA ?
    Thanks

    #35226
    HerveM1234
    Participante

    Hi,

    Why the syntax : [code]
    fileToOpen = Application _
    .GetOpenFilename(“Text Files (*.txt), *.txt”)
    If fileToOpen False Then
    MsgBox “Open ” & fileToOpen
    End If
    [/code]
    returns “error 438” ?

    How to browse directories using FlexPro VBA ?
    Thanks

    #35225
    Bernhard Kantz
    Keymaster

    GetOpenFilename() is (as the error 438 states) no part of the FlexPro object model. It is a function from the Win32 API (and also mimicked by MS Office applications).
    You may use the FileDialog property to display a file chooser. An example can be found in the online help (Index: FpFileDialog (object), follow Example link).

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